If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2=1-9x
We move all terms to the left:
6x^2-(1-9x)=0
We add all the numbers together, and all the variables
6x^2-(-9x+1)=0
We get rid of parentheses
6x^2+9x-1=0
a = 6; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·6·(-1)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{105}}{2*6}=\frac{-9-\sqrt{105}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{105}}{2*6}=\frac{-9+\sqrt{105}}{12} $
| 5u+25=25 | | 2x/5+7=17 | | -4x+36=3x-4 | | 4x-36=3x-4 | | (x-9)/2=3x-4/8 | | (8x+15)=(4x+25) | | (8x+5)=(4x+22) | | (11x+6)=(14x-12) | | 2l+2W=220 | | I2x-3I=4x-1 | | -15=12-4c | | 4(x+5)=(x+2)(x+2) | | 4(x+5)=x+2 | | (x+5)+4=x+2 | | Y=x+31 | | 44-3x=5x | | 9+(6+B)=(6+x)+B | | 48-(3x+4)=4(x+5)x | | 4x+12=224 | | 20+5.50h=15+6. | | 2x-9=-3x+4 | | M^2-9m=53 | | 6x^2-40x-24=0 | | -d+11-4d-9d=-17 | | 3/k=7.5 | | (8x-5)+(x+5)=180 | | x+52-4x+140=180 | | -u+273=201 | | 201=126-y | | 2(81-4.5y)+9=162 | | -13-4x=x-11 | | 3(x1)-5=5x-2 |